Indices & the Law of Indices
Question
Simplify \(\left(3a\right)^{-2}\)
Solution
Show solution Hide solution Fully worked — 3 steps
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Apply the negative-index law \(a^{-m} = \frac{1}{a^{m}}\)\[ \left(3a\right)^{-2} = \frac{1}{\left(3a\right)^{2}} \]
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Apply the power-of-a-product law \((ab)^{n} = a^{n}b^{n}\)\[ = \frac{1}{3^{2}a^{2}} \]
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Evaluate \(3^{2}\)\[ \left(3a\right)^{-2} = \frac{1}{9a^{2}} \]
That is, the simplified expression is 1 over 9 a squared.